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CGP EDU Academic Team
Published on: August 13, 2026
Enthalpies of solution of BaCl 2 (s) and BaCl 2 .2H 2 O (s) are – 20 kJ/mole and 8.0 kJ/mole respectively. Calculate heat of hydration of BaCl 2 (s).
Text Solution
Verified by ExpertsThe correct answer is:
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(– 28 kJ/mole )
Given : Enthalpies of solution are :
BaCl 2 (s) + 2H 2 O ( λ ) + (aq) ⎯→ BaCl 2 .2H 2 O (s) ; Δ H = – 20 kJ/mole ...(I)
BaCl 2 .2H 2 O (s) + (aq) ⎯→ BaCl 2 .2H 2 O (aq) ; Δ H = 8 kJ/mole ...(II)
Subtract (I) and (II)
BaCl 2 (s) + 2H 2 O ( λ ) + (aq) ⎯→ BaCl 2 .2H 2 O (s) ; Δ H = – 20 – 8 = – 28 kJ/mole
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